List of Shane episodes - Wikimedia list article. Article “Episodi di Shane” in Italian Wikipedia has 20.8 points for quality (as of July 1, 2025). The article contains 0 references and 35 sections. The article also contains templates indicating quality issues, therefore its score was reduced by 1.1 points.
Since the creation of article “Episodi di Shane”, its content was written by 11 registered users of Italian Wikipedia and edited by 11 registered Wikipedia users in all languages.
The article is cited 29 times in Italian Wikipedia and cited 29 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Italian: #533640 02.2022 |
Global: #6304646 02.2022 |
| Best Rank | Italian: #4170 02.2022 |
Global: #217060 02.2022 |
On 5 March 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: Iran, Ali Khamenei, 2026 Iran war, Jeffrey Epstein, Kurds, Strait of Hormuz, Yakovlev Yak-130, Donald Trump, Azerbaijan, Kristi Noem.
In Italian Wikipedia the most popular articles on that day were: Basi militari statunitensi in Italia, Sal Da Vinci, Budorcas taxicolor, Iran, Ditonellapiaga, Samurai Jay, Festival di Sanremo 2026, Luigi XVI di Francia, Episodi di Mare fuori (sesta stagione), Henry John Woodcock.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(9.58+0+0+100+0)-1.1$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
